Python Program to Print A-ABA-ABCBA Pattern Up To n Lines

This program prints A-ABA-ABCBA pattern up to n lines given by user.

In this program %c is used for displaying corresponding ASCII character of a number. For example to display ASCII character corresponding to 66; print("%c" %(66)) which gives B as output.

Python Source Code: A-ABA-ABCBA Pattern

# A-ABA-ABCBA pattern

# Reading number of rows
row = int(input('Enter how many lines? '))

a = 64
# Generating pattern
for i in range(1,row+1):
    
    # for space
    for j in range(1, row+1-i):
        print(' ', end='')
    
    # for increasing pattern
    for j in range(1,i+1):
        print('%c' %(a+j), end='')
    
    # for decreasing pattern 
    for j in range(i-1,0,-1):
        print('%c' %(a+j), end='')
    
    # Moving to next line
    print()

Output

Enter how many lines? 6

     A
    ABA
   ABCBA
  ABCDCBA
 ABCDEDCBA
ABCDEFEDCBA